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COMPUTER COMPUTATION OF THE OPTICAL TRANSFER FUNCTION

171

(d) The total area A under Hð fx; fyÞ equals 8s2. The OTF is given by

ðð1

HI ð fx; fyÞ ¼ Hð fx0; fy0ÞH ð fx0 fx; fy0 fyÞd fx0d fy0

1

A

The computation of the above integral is not trivial and can be best done by the computer.

10.9 COMPUTER COMPUTATION OF THE OPTICAL TRANSFER FUNCTION

The easiest way to compute the discretized OTF is by using the FFT. For this purpose, both hðx; yÞ; Hð fx; fyÞ and HI ð fx; fyÞ, have to be discretized. The discretized coordinates can be written as follows:

x ¼ xn1

ð10:9-1Þ

y ¼ yn2

ð10:9-2Þ

fx ¼ fxk1

ð10:9-3Þ

fy ¼ fyk2

ð10:9-4Þ

hð xn1; yn2Þ, Hð fxk1; fyk2Þ, and HI ð fxk1; fyk2Þ will

be written as

hðn1; n2Þ, Hðk1; k2Þ, and HI ðk1; k2Þ, respectively. The size of the matrices involved are assumed to be N1, by N2. In order to use the FFT, the following must be satisfied:

x fx ¼

1

ð10:9-5Þ

N1

y fy ¼

1

ð10:9-6Þ

N2

hðn1; n2Þ is approximately given by

hðn1; n2Þ ¼

1

h0ðn1; n2Þ

ð10:9-7Þ

K

where

N1

1

N2

1

h0ðn1; n2

Þ ¼ k1

N1

k2

N2 Hðk1; k2Þej2p N1 þ N2

ð10:9-8Þ

X

X

2

2

n1k1 n2k2

¼

¼

2

2


172

IMAGING WITH QUASI-MONOCHROMATIC WAVES

and

K ¼ x yN1N2

ð10:9-9Þ

Hðk1; k2Þ equals Pð ld0 fxk1; ld0 fyk2Þ. N1 and N2 should be chosen such that the pupil function is sufficiently represented. For example, the nonzero portion of the pupil function must be completely covered. In order to minimize the effect of periodicity imposed by the FFT, N1 and N2 should be at least twice as large the minimum values dictated by the nonzero portion of the pupil function.

Once N1 and N2 are properly chosen, Hðk1; k2Þ is arranged as discussed in Section 4.4 so that k1 and k2 satisfy 0 k1 < N1 and 0 k2 < N2 respectively.

HI ðk1; k2Þ is approximately given by

x y N1 1 N2 1

n1k1

n2k2

0 jh0ðn1; n2Þj2e j2p

þ

N1

N2

HI

ð

k1

; k2

Þ ¼

K2

n1

¼

0

n2

¼

ð

10:9-10

Þ

1

N1

1 N2 1

X X

X X

K

k1¼0

jHðk1; k2Þj2

k2¼0

or

0

n2 0 jh0ðn1; n2Þj2e j2p

N1 þ N2

N11N2

n1

N1

1 N2

1

n1k1

n2k2

HI

ð

k1

; k2

Þ ¼

¼

¼

ð

10:9-11

Þ

N1 1 N2 1

X X

X X

jHðk1; k2Þj2

k1¼0

k2¼0

The numerator above is the 2-D DFT of jh0ðn1; n2Þj2. HI ðk1; k2Þ above is actually shifted to positive frequencies because of the underlying periodicity. It should be shifted down again to include negative frequencies.

In summary, Hðk1; k2Þ is determined by using the pupil function. h0ðn1; n2Þ is obtained by the inverse DFT of Hðk1; k2Þ according to Eq. (10.9-8). HI ðk1; k2Þ is given by the DFT of jh0ðn1; n2Þj2 normalized by the area under jHðk1; k2Þj2.

Note that fx and fy should be chosen small enough so that h0ðn1; n2Þ is not aliased when computed by using Eq. (10.9-8). Once fx and fy are chosen, N1 and N2 are determined by considering the pupil function as discussed above.

10.9.1Practical Considerations

In studies of the OTF and MTF, ld0 is often chosen to be equal to 1, and the negative signs in the pupil function are neglected so that Hðfx; fyÞ is simply written as Pð fx; fyÞ. Normalization by the area of the pupil function may also be neglected.


ABERRATIONS

173

Another way to generate OTF is by autocorrelating the pupil function with itself.

10.10ABERRATIONS

A diffraction-limited system means the wave of interest is perfect at the exit pupil, and the only imperfection is the finite aperture size. The wave of interest is typically a spherical wave. Aberrations are departures of the ideal wavefront within the exit pupil from its ideal form. They are typically phase errors.

In order to include aberrations, the exit pupil function can be modified as

PAðx; yÞ ¼ Pðx; yÞe jkfAðx;yÞ

ð10:10-1Þ

where Pðx; yÞ is the exit pupil function without aberrations, and fAðx; yÞ is the phase error due to aberrations.

The theory of coherent and incoherent imaging developed in the previous sections is still applicable with the replacement of Pðx; yÞ by PAðx; yÞ. For example, the amplitude transfer function becomes

Hðfx; fyÞ ¼ PAð ld0 fx; ld0 fyÞ

ð10:10-2Þ

¼ Pð ld0 fx; ld0 fyÞe jkfAð ld0 fx; ld0 fyÞ

The optical transfer function can be similarly written as

HI ð fx; fyÞ ¼

1

Að fx; fyÞ

ð10:10-3Þ

ðð Pðld0 fx; ld0 fyÞdfxdfy

1

where

ðð

PA fx0 þ l 2 ; fy0 þ l

PA fx0 l 2 ; fy0

l 2

d fx0d fy0

Að fx; fyÞ ¼

2

1

d0 fx

d0 fy

d0 fx

d0 fy

1

ð10:10-4Þ

Note that Að fx; fyÞ is to be computed in the area of overlap of the two pupil functions shifted with respect to each other. The ordinary pupil function in this area

equals 1. Letting

denote integration in the area of overlap, Aðfx; fyÞ can be

written as

overlap

Ð Ð

Að fx; fyÞ ¼overlapðð

P1P2d fx0d fy0

ð10:10-5Þ


174

IMAGING WITH QUASI-MONOCHROMATIC WAVES

where

jkf f 0

ld0fx

; f 0

ld0fy

P1

¼ e

A

þ

ld0fx

y

þ

ld0

fy

x

2

2

P2 ¼ e jkfA fx0

; fy0

2

2

ð10:10-6Þ

ð10:10-7Þ

EXAMPLE 10.10 Show that aberrations do not increase the MTF.

Solution: The MTF is the modulus of the OTF. According to the Schwarz’s inequality, it is true that

ðð

ðð

j

A

f

; f

2

j

P

1j

2d f 0d f 0

j

P

2df 0d f 0

ð x

yÞj

x y

2j

x y

overlap

overlap

Note that

jP1j2 ¼ jP2j2 ¼ 1

in the area of overlap. Hence, jAð fx; fyÞj2 area of overlap, and

jHI ð fx; fyÞj2 jHI0ð fx; fyÞj2

where HI0ð fx; fyÞ is the optical transfer function without aberrations.

ð10:10-8Þ

ð10:10-9Þ

ð10:10-10Þ

The phase function fAðx; yÞ is often written in terms of the polar coordinates as fAðr; yÞ. What is referred to as Seidel aberrations is the representation of fAðr; yÞ as a polynomial in r, for example,

fAðr; yÞ ¼ a40r4 þ a31r3 cos y þ a20r2 þ a22r2 cos2 y þ a11r cos y ð10:10-11Þ

Higher order terms can be added to this function. The terms on the right hand side of Eq. (10.9-11) represent the following:

a40r4

:

spherical aberration

a31r3 cos y :

coma

a20r2

:

astigmatism

a22r2 cos2 y :

field curvature

a11r cos y :

distortion

10.10.1Zernike Polynomials

When the exit pupil of the optical system is circular, the aberrations present in an optical system can be represented in terms of Zernike polynomials, which are


ABERRATIONS

175

Table 10.1. The Zernike polynomials.

No.

Polynomial

1

1

2

2r cosðyÞ

3

2r sinðyÞ

1

r

p3ð2r2

r

cos 2y

4

p3

2

2

5

p6ð

2

Þ

r sin 2y

Þ

r

ð

2 r cos y

6

p6

2

ð

Þ

r

2 r sin y

7

p8 3

2

8

p8ð3 2

Þ

ð Þ

9

r

6r

1

p5ð6

4

Þ

2

ð Þ

10

r

cos 3y

þ

Þ

p8ð

3

r sin 3y

Þ

r

ð

3 r cos 2y

11

p8

3

ð

Þ

r

3 r sin 2y

12

p10 4

2

Þ

2

ð

Þ

ð

r

12r

3 r cos y

13

p10 4

2

Þ

2

ð

Þ

ð

r

12r

3 r sin y

14

p12 10

4

2

þ

Þ

ð Þ

ð

r

30r

12r

1

15

p12 10

4

2

þ

Þ

ð Þ

ð

r

cos 4y

16

p7

ð

20

6

4

þ

2

Þ

r

sin 4y

17

p10

4

ð

Þ

r

4 r cos 3y

18

p10

4

ð

Þ

r

4 r sin 3y

19

p12 5

2

Þ

3

ð

Þ

ð

r

20r

6 r cos 2y

20

p12 5

2

Þ

3

ð

Þ

ð

r

20r

6 r sin 2y

21

p14 15

4

2

þ

Þ

2

ð

Þ

23

ð

r

y

4 r

r

r

22

p14 15

4

2

þ

Þ

2

ð

Þ

ð

ð

35

6

60

4

þ

30

2

4

Þ

cos

ð Þ

24

4ð35r6 60r4 þ 30r2 4Þr sinðyÞ

25

3ð70r8 140r6 þ 90r4 20r2 þ 1Þ

27

r

sin 5y

26

p12r5 cosð5yÞ

28

r

5 r cos 4y

p12

5

ð

Þ

29

r

5 r sin 4y

p14 6

2

Þ

4

ð

Þ

30

ð

4 r

30r

10 r cos 3y

p14 6

2

Þ

4

ð

Þ

ð

ð

21

4

2

þ

Þ

3

ð

Þ

31

4ð21r4 30r2 þ 10Þr3 sinð3yÞ

33

ð

r

105r

þ 60r

10Þr sinð2yÞ

32

p18ð56r6

105r4

þ 60r2

10Þr2 cosð2yÞ

34

r

280r

210r

60r

5 r cos y

35

p18 56

6

4

2

2

5 r sin y

r

280r

210r

60r

p20 126

8

6

þ

4

2

þ

Þ

ð Þ

36

ð

r

ð

630r

þ 560r

210r

þ 30r

p20 126

8

6

þ

4

2

þ

Þ

ð Þ

37

ð

r

42r 1

2772r

3150r 1680r

420r

p11 252

10

8

þ

6

4

2

þ Þ

p

12

10

8

6

þ

4

2

13 924

ð